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Ray Optics and Optical Instruments - ISC Class 12 Physics Questions with Answers, Page 2

122 past-paper questions on Ray Optics and Optical Instruments from ISC Class 12 Physics papers (2027-2018), newest first, in full. Questions 21-40 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2026 · 2 marks · NumericalOpen: A bi-convex lens of focal length is placed in air as shown in Figure 3(a)…

Solve the following.

A bi-convex lens of focal length $f_{1}$ is placed in air as shown in Figure 3(a) below. The radii of curvature of its first and second surfaces are R and 2R respectively. The lens is cut along the plane CD. Compare the focal length $f_{2}$ of the resulting lens shown in Figure 3(b) with that of the original lens shown in Figure 3(a).
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Answer

AI
Using the Lens Maker's Formula: $\frac{1}{f} = (\mu - 1)\left(\frac{1}{R_{1}} - \frac{1}{R_{2}}\right)$ For the original bi-convex lens (Figure 3(a)): $R_{1} = +R$ and $R_{2} = -2R$ $\frac{1}{f_{1}} = (\mu - 1)\left(\frac{1}{R} - \left(-\frac{1}{2R}\right)\right) = (\mu - 1)\frac{3}{2R}$ $f_{1} = \frac{2R}{3(\mu - 1)}$ For the cut lens (Figure 3(b)): The first surface is plane ($R_{1}' = \infty$) and the second surface has radius $R_{2}' = -2R$: $\frac{1}{f_{2}} = (\mu - 1)\left(\frac{1}{\infty} - \left(-\frac{1}{2R}\right)\right) = (\mu - 1)\frac{1}{2R}$ $f_{2} = \frac{2R}{\mu - 1}$ Comparing the focal lengths: $\frac{f_{2}}{f_{1}} = \frac{\frac{2R}{\mu - 1}}{\frac{2R}{3(\mu - 1)}} = 3 \implies f_{2} = 3f_{1}$

Final answer: 3

2026 · 3 marks · DrawingOpen: Draw a labelled diagram of an astronomical telescope when its final image lies…

Draw the following.

Draw a labelled diagram of an astronomical telescope when its final image lies at infinity.

Draw: ray diagram of an astronomical telescope when its final image lies at infinity (normal adjustment)

Must show: objective lens, eyepiece, parallel rays from distant object, intermediate real, inverted image at focus Fo and Fe, parallel rays emerging from eyepiece

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Answer

AI
A labelled ray diagram of an astronomical telescope in normal adjustment consists of a large-aperture, long-focal-length objective lens and a smaller eyepiece separated by $L = f_o + f_e$. Parallel rays from a distant object enter the objective at angle $\alpha$ and form a real, inverted, diminished intermediate image $A'B'$ at the common focal plane ($F_o$ coincides with $F_e$). The rays then refract through the eyepiece and emerge as parallel rays entering the observer's eye at angle $\beta$, forming the final inverted image at infinity.
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2026 · 3 marks · Short answerOpen: Consider two thin lenses, M and N having focal lengths of and , respectively…

Answer the following.

Consider two thin lenses, M and N having focal lengths of $f_{1}$ and $f_{2}$, respectively. They are kept in contact with each other as shown in Figure 6 below. A point object 'S' is kept on the common principal axis. The first lens M forms an image at $I_{1}$, which serves as a virtual object for the second lens N. The final image formed by the combination is 'I'.
Figure for this question
(i)[2.0]
Apply the lens formula for the formation of: (a) Image $I_{1}$ by the first lens M. (b) Image I by the second lens N.
(ii)[1.0]
Hence, obtain an expression for equivalent focal length (F) in terms of $f_{1}$ and $f_{2}$.

To show: $\frac{1}{F} = \frac{1}{f_{1}} + \frac{1}{f_{2}}$

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2026 · 1 mark · One wordOpen: The image below shows a compound microscope. Which one of the two lenses or has…

Answer in one word.

The image below shows a compound microscope. Which one of the two lenses $L_{1}$ or $L_{2}$ has a larger focal length?
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Answer

AI
Lens $L_1$ has a larger focal length. In a compound microscope, $L_1$ is the eyepiece and $L_2$ is the objective. The eyepiece has a larger focal length (and larger aperture) than the objective lens ($f_e > f_o$) to provide appropriate magnification and a comfortable field of view.
2025 · 3 marks · NumericalOpen: Two convex lenses having focal length of and are placed coaxially to form a…

Solve the following.

Two convex lenses having focal length of $1.5\text{ cm}$ and $5\text{ cm}$ are placed coaxially to form a compound microscope. When a pin is kept at a distance of $1.6\text{ cm}$ from the objective lens, a virtual magnified image is formed at a distance of $25\text{ cm}$ from the eyepiece. Calculate the length of the microscope.

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2025 · 1 mark · Short answerOpen: figure 1

Answer the following.

figure 1

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2025 · 1 mark · DrawingOpen: Figure 3 below shows an optical pin kept in front of a lens mirror combination…

Draw the following.

Figure 3 below shows an optical pin kept in front of a lens mirror combination. It is found that the final image formed by the lens mirror combination coincides with the object pin. Draw the ray diagram showing the formation of the final image (I).

Draw: ray diagram showing the formation of the final image (I)

Must show: formation of the final image (I), optical pin, lens mirror combination

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