Prashnikaप्रश्निका
‹ Back to the paper

Solve the following.

A monochromatic ray of light incident on one refracting surface of an equilateral prism, suffers a…

Physics20263 marksNumerical
A monochromatic ray of light incident on one refracting surface of an equilateral prism, suffers a deviation as shown in the Figure 7 below:
Figure for this question
(i)[2.0]
Calculate the refractive index of the material of the prism.
(ii)[1.0]
What is meant by dispersive power of a transparent material?

Answer

Answer (i)

AI
From Figure 7, the refracted ray inside the equilateral prism is parallel to the base, which means the prism is in the minimum deviation position ($\delta_m = 40^\circ$). For an equilateral prism, angle of prism $A = 60^\circ$. Using the prism formula: $\mu = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$ $\mu = \frac{\sin\left(\frac{60^\circ + 40^\circ}{2}\right)}{\sin\left(\frac{60^\circ}{2}\right)} = \frac{\sin 50^\circ}{\sin 30^\circ} = \frac{0\cdot766}{0\cdot5} = 1\cdot532 \approx 1\cdot53$

Final answer: 1.53

Answer (ii)

AI
Dispersive power ($\omega$) of a transparent material is defined as the ratio of angular dispersion between two extreme colours (violet and red) to the mean deviation produced by a thin prism of that material: $\omega = \frac{\delta_V - \delta_R}{\delta_Y} = \frac{\mu_V - \mu_R}{\mu_Y - 1}$
Ray Optics and Optical Instruments

From ISC 2026 Physics Paper 1, question 13.