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Boolean Algebra - ISC Class 12 Computer Science Questions with Answers, Page 6

189 past-paper questions on Boolean Algebra from ISC Class 12 Computer Science papers (2026-2017), newest first, in full. Questions 101-120 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2023 · 1 mark · One wordOpen: Verify if is a Tautology, Contradiction, or a Contingency.

Answer the following.

Verify if $(A + A')'$ is a Tautology, Contradiction, or a Contingency.
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Answer

AI
AA'A + A'(A + A')'
0110
1010
Since $A + A' = 1$, $(A + A')' = 1' = 0$ for every value of A. The output is always 0, so it is a Contradiction.
2023 · 1 mark · One wordOpen: Write the minterm of when and .

Answer the following.

Write the minterm of $F(A, B, C, D)$ when $A = 1, B = 0, C = 0$ and $D = 1$.
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Answer

AI
In a minterm a variable with value 1 is written as it is and a variable with value 0 is complemented. Minterm $= A \cdot B' \cdot C' \cdot D$ (i.e. $AB'C'D$, $m_9$).
2023 · 1 mark · MCQOpen: The reduced expression of the Boolean function is:

Answer the following.

The reduced expression of the Boolean function $F(P, Q) = P' + PQ$ is:
  • (a)$P' + Q$
  • (b)$P$
  • (c)$P'$
  • (d)$P + Q$
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Answer

AI

Correct option: (a)

Answer: (a) $P' + Q$ $P' + PQ = (P' + P)(P' + Q) = 1 \cdot (P' + Q) = P' + Q$ (distributive law, then complement law).
2023 · 2 marks · ConversionOpen: Convert the following cardinal expression to its canonical form:

Answer the following.

Convert the following cardinal expression to its canonical form: $F(P, Q, R) = \pi(0, 1, 3, 4)$
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Answer

AI
$F(P, Q, R) = \pi(0, 1, 3, 4)$: write each maxterm in binary; a 0 bit gives the variable as it is and a 1 bit gives its complement, and the variables within a term are added. $0 = 000 \to (P + Q + R)$ $1 = 001 \to (P + Q + R')$ $3 = 011 \to (P + Q' + R')$ $4 = 100 \to (P' + Q + R)$ Canonical form: $F(P, Q, R) = (P + Q + R) \cdot (P + Q + R') \cdot (P + Q' + R') \cdot (P' + Q + R)$
2023 · 5 marks · Case basedOpen: Given the Boolean function . Reduce the above expression by using 4-variable…

Reduce the following using a Karnaugh map.

Given the Boolean function $F(A, B, C, D) = \Sigma(0, 1, 2, 3, 4, 6, 9, 11, 13)$.
(a)[4.0]
Reduce the above expression by using 4-variable Karnaugh map, showing the various groups (i.e. octal, quads and pairs).
(b)[1.0]
Draw the logic gate diagram for the reduced expression. Assume that the variables and their complements are available as inputs.

Draw: Logic gate diagram for the reduced expression

Must show: variables and their complements as inputs

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Answer (b)

AI
Logic gate diagram for $F = A'D' + B'D + AC'D$: two 2-input AND gates and one 3-input AND gate feeding a 3-input OR gate.
Diagram for this answer
2023 · 1 mark · MCQOpen: The dual of is:

Choose the correct option.

The dual of $(P + P') \cdot (Q + 0) = Q$ is:
  • (a)$P \cdot P' + Q \cdot 1 = Q$
  • (b)$P \cdot P' + Q \cdot 0 = Q$
  • (c)$P \cdot P + Q \cdot 1 = Q'$
  • (d)$P + P' + Q + 1 = Q$
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Answer

AI

Correct option: (a)

Answer: (a) $P \cdot P' + Q \cdot 1 = Q$ The dual of an expression is formed by interchanging every $+$ with $\cdot$ and every $0$ with $1$ (variables are left unchanged): $(P+P')\cdot(Q+0)=Q$ becomes $(P\cdot P')+(Q\cdot 1)=Q$.
2023 · 5 marks · Truth tableOpen: A family intends to purchase a smart phone depending on the criteria given…

Answer the following using a truth table.

A family intends to purchase a smart phone depending on the criteria given below: • Quad core processor with internal memory of 64 GB or more but not a resale phone OR • Resale phone with quad core processor but without warranty OR • Processor is not a quad core but with a warranty of 1 year and the internal memory is of 64 GB or more The inputs are:
INPUTS
PQuad core processor
MInternal memory of 64 GB or more
RResale phone
WWarranty of 1 year
(In all the above cases, 1 indicates yes and 0 indicates no.) Output: X [1 indicates purchased, 0 indicates not purchased for all cases] Draw the truth table for the inputs and outputs given above and write the SOP expression

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2023 · 1 mark · MCQOpen: If then, its inverse will be:

Choose the correct option.

If $(x \Rightarrow \sim y)$ then, its inverse will be:
  • (a)$x \Rightarrow y$
  • (b)$y \Rightarrow x$
  • (c)$\sim y \Rightarrow x$
  • (d)$\sim x \Rightarrow y$
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Answer

AI

Correct option: (d)

Answer: (d) $\sim x => y$ For an implication $p \Rightarrow q$, its inverse is $\sim p \Rightarrow \sim q$. Here $p=x$ and $q=\sim y$, so the inverse is $\sim x \Rightarrow \sim(\sim y) = \sim x \Rightarrow y$.
2022 · 1 mark · MCQOpen: The Quad group in a Karnaugh’s map eliminates:

Choose the correct option.

The Quad group in a Karnaugh’s map eliminates:
  • (a)One variable
  • (b)Four variables
  • (c)Three Variables
  • (d)Two variables
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Answer

AI

Correct option: (d)

Answer: (d) Two variables A quad (group of 4 cells) eliminates two variables; a pair eliminates one and an octet three.
2022 · 1 mark · MCQOpen: The propositional operator represents:

Choose the correct option.

The propositional operator $=>$ represents:
  • (a)Conjunction
  • (b)Implication
  • (c)Disjunction
  • (d)Negation
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Answer

AI

Correct option: (b)

Answer: (b) Implication The operator => stands for implication (if ... then).
2022 · 1 mark · MCQOpen: the converse of the proposition is:

Choose the correct option.

the converse of the proposition is:
  • (i)~Q => P
  • (ii)Q => ~P
  • (iii)~Q => ~P
  • (iv)~P => ~Q
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With reference to the given proposition $\sim P => Q$, answer the following questions:
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Answer

AI

Correct option: (ii)

Answer: (ii) Q => ~P The converse of A => B is B => A. Here A = ~P, B = Q, so the converse is Q => ~P.
2022 · 2 marks · MCQOpen: The reduced expression of the Boolean function given above is:

Choose the correct option.

The reduced expression of the Boolean function given above is:
  • (i)$(B + C) \cdot (B + D) \cdot (A' + D)$
  • (ii)$BC + BD + A'D$
  • (iii)$AB' + C'D' + B'D'$
  • (iv)$(A + B') \cdot (C' + D') \cdot (B' + D')$
Show the case
Reduce the given Boolean function $F(A,B,C,D) = \pi(3,4,5,6,7,11,13,15)$ by using 4-variable Karnaugh map and answer the following questions:
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Answer

AI

Correct option: (iv)

Answer: (iv) $(A + B') \cdot (C' + D') \cdot (B' + D')$ The three quads give $(A+B')$ (4,5,6,7), $(B'+D')$ (5,7,13,15) and $(C'+D')$ (3,7,11,15).
2022 · 2 marks · MCQOpen: The complement of the expression:

Choose the correct option.

The complement of the expression:
  • (i)$P'R' + (P' + Q') \cdot (Q' + R)$
  • (ii)$(P' + R') \cdot (P' + Q') + (Q + R')$
  • (iii)$P'R' \cdot (PQ' + Q'R)$
  • (iv)$(P + R)' \cdot (P' + Q) \cdot (Q' + R)$
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Given the Boolean expression $F = (P + R) \cdot (P \cdot Q + Q \cdot R')$, identify:
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Answer

AI

Correct option: (i)

Answer: (i) $P'R' + (P' + Q') \cdot (Q' + R)$ By De Morgan's law, $F' = (P+R)' + (PQ + QR')' = P'R' + (P'+Q')(Q'+R)$.
2022 · 1 mark · MCQOpen: the contra-positive of the proposition is:

Choose the correct option.

the contra-positive of the proposition is:
  • (i)~P => Q
  • (ii)Q => P
  • (iii)~Q => P
  • (iv)~P => ~Q
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Answer

AI

Correct option: (iii)

Answer: (iii) ~Q => P The contrapositive of A => B is ~B => ~A. Here it is ~Q => ~(~P) = ~Q => P.
2022 · 2 marks · MCQOpen: The POS expression for will be:

Choose the correct option.

The POS expression for $X(A,B,C,D)$ will be:
  • (i)$F(A,B,C,D) = \sum(3, 5, 7, 11, 12, 13, 14, 15)$
  • (ii)$F(A,B,C,D) = \pi(3, 5, 7, 11, 12, 13, 14, 15)$
  • (iii)$F(A,B,C,D) = \pi(0, 1, 2, 4, 6, 8, 9, 10)$
  • (iv)$F(A,B,C,D) = \sum(0, 1, 2, 4, 6, 8, 9, 10)$
Show the case
A school intends to select candidates for an Inter school competition as per the criteria given below: • The student has participated in an earlier competition and is very creative Or • The student is very creative and has excellent general awareness, but has not participated in any competition earlier Or • The student has excellent general awareness and has won prize in an inter-house competition The inputs are:
Inputs
AParticipated in a competition earlier
BIs very creative
CWon prize in an inter house competition
DHas excellent general awareness
(In all the above cases 1 indicates yes and 0 indicates no). Output: X [1 indicates yes and 0 indicates no for all cases].
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Answer

AI

Correct option: (iii)

Answer: (iii) $F(A,B,C,D) = \pi(0, 1, 2, 4, 6, 8, 9, 10)$ X = AB + A'BD + CD, which is 1 for minterms 3,5,7,11,12,13,14,15. The POS form lists the remaining maxterms 0,1,2,4,6,8,9,10.
2022 · 1 mark · MCQOpen: The proposition is represented by:

Choose the correct option.

The proposition $(a <=> b)$ is represented by:
  • (a)$a'b' + ab$
  • (b)$(a' + b') \cdot (a + b)$
  • (c)$(a + b)'$
  • (d)$(a \cdot b)'$
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Answer

AI

Correct option: (a)

Answer: (a) $a'b' + ab$ The biconditional a <=> b is true when both are equal: $ab + a'b'$ (XNOR).
2022 · 1 mark · MCQOpen: The law which represents the Boolean equation is:

Choose the correct option.

The law which represents the Boolean equation $A + B = B + A$ is:
  • (a)Associative Law
  • (b)Distributive Law
  • (c)Commutative Law
  • (d)Absorption Law
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Answer

AI

Correct option: (c)

Answer: (c) Commutative Law A + B = B + A shows the order of operands does not matter, which is the Commutative Law.
2022 · 1 mark · MCQOpen: The complement of the Boolean expression is:

Choose the correct option.

The complement of the Boolean expression $F(P,Q,R) = (P + Q + R)$ is:
  • (a)$P'Q'R'$
  • (b)$P' + Q' + R'$
  • (c)$P + (Q' + R')$
  • (d)$(P + Q) + R'$
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Answer

AI

Correct option: (a)

Answer: (a) $P'Q'R'$ By De Morgan's law, $(P+Q+R)' = P'Q'R'$.
2022 · 1 mark · MCQOpen: If and , then the maxterm will be:

Choose the correct option.

If $A = 1, B = 0, C = 0$ and $D = 1$, then the maxterm will be:
  • (a)$AB'C'D$
  • (b)$A'BCD'$
  • (c)$A + B' + C' + D$
  • (d)$A' + B + C + D'$
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Answer

AI

Correct option: (d)

Answer: (d) $A' + B + C + D'$ A maxterm is a sum in which a variable appears complemented if its value is 1 and uncomplemented if 0. For A=1, B=0, C=0, D=1 this gives $A' + B + C + D'$.

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