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Current Electricity - ISC Class 12 Physics Questions with Answers, Page 4

103 past-paper questions on Current Electricity from ISC Class 12 Physics papers (2027-2018), newest first, in full. Questions 61-80 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2023 · 3 marks · NumericalOpen: In a meter bridge circuit, resistance in the left gap is and an unknown…

Solve the following.

In a meter bridge circuit, resistance in the left gap is $4\,\Omega$ and an unknown resistance $R$ is in the right-hand gap as shown in Figure 2 below. The null point is found to be $40\text{ cm}$ from the left end of the wire.
Figure for this question
(a)[1.5]
Calculate the value of the unknown resistance $R$.
(b)[1.5]
What change will you make in $R$ to bring the null point to the midpoint of the wire AB?

No answer yet.

2023 · 3 marks · DrawingOpen: A circuit is used to determine the internal resistance and the emf of a cell…

Solve the following.

A circuit is used to determine the internal resistance and the emf of a cell. It consists of the cell, a variable resistor, an ideal ammeter A and an ideal voltmeter V. Figure 3 shows part of the circuit with the ammeter and voltmeter missing. The variable resistor is set to be $1\cdot5\,\Omega$. When the cell converts $7\cdot2\text{ mJ}$ of energy, $5\cdot8\text{ mC}$ of charge moves completely around the circuit. The potential difference across the variable resistor is $0\cdot55\text{ V}$.
Figure 3
Figure 3
(a)[1.5]
Redraw the diagram showing the positions of the ammeter and the voltmeter.
(b)[1.5]
Calculate the emf of the cell.

No answer yet.

2023 · 3 marks · NumericalOpen: Eight identical cells, each of emf and internal resistance , are connected in…

Solve the following.

Eight identical cells, each of emf $2\text{ V}$ and internal resistance $3\,\Omega$, are connected in series to form a row. Six such rows are connected in parallel to form a battery. This battery is now connected to an external resistor R of resistance $6\,\Omega$. Calculate:
(a)[1.0]
emf of the battery.
(b)[1.0]
internal resistance of the battery.
(c)[1.0]
current flowing through R.

No answer yet.

2022 · 1 mark · MCQOpen: The circuit shown in figure 9 below is used to compare the e.m.f. of two cells…

Choose the correct option.

The circuit shown in figure 9 below is used to compare the e.m.f. of two cells $E_1$ and $E_2$ where $E_2 > E_1$. The null point is at C when the galvanometer is connected to $E_1$. When the galvanometer is connected to $E_2$, the null point will be:
  • (a)To the left of C
  • (b)To the right of C
  • (c)At C itself
  • (d)Nowhere on AB
Figure for this question

No answer yet.

2022 · 2 marks · Case basedOpen: A torch bulb rated as 4.5 W, 1.5 V is connected as shown in figure 12 given…

Study the information given and answer the questions that follow.

A torch bulb rated as 4.5 W, 1.5 V is connected as shown in figure 12 given below.
Figure for this question
(i)[1.0]
What should be the e.m.f. of the cell required to make this bulb glow at full intensity?
  • (a)$4.5\text{ V}$
  • (b)$1.5\text{ V}$
  • (c)$2.67\text{ V}$
  • (d)$13.5\text{ V}$
(ii)[1.0]
What is the current passing through $1\ \Omega$ resistor?
  • (a)$4.5\text{ A}$
  • (b)$1.5\text{ A}$
  • (c)$2.67\text{ A}$
  • (d)$13.5\text{ A}$

No answer yet.

2022 · 1 mark · MCQOpen: A cell of e.m.f. E is connected to an external resistance R. The potential…

Choose the correct option.

A cell of e.m.f. E is connected to an external resistance R. The potential difference across cell is V. The internal resistance of cell will be:
  • (a)$\left(\frac{E-V}{E}\right)R$
  • (b)$\left(\frac{E-V}{V}\right)R$
  • (c)$\left(\frac{V-E}{V}\right)R$
  • (d)$\left(\frac{V-E}{E}\right)R$

No answer yet.

2022 · 2 marks · Case basedOpen: The specific resistance of manganin is . The resistance of a cube of length 50m…

Study the information given and answer the questions that follow.

The specific resistance of manganin is $50 \times 10^{-8}\ \Omega\text{ m}$.
(i)[1.0]
The resistance of a cube of length 50m will be:
  • (a)$10^{-6}\ \Omega$
  • (b)$2.5 \times 10^{-5}\ \Omega$
  • (c)$10^{-8}\ \Omega$
  • (d)$50 \times 10^{-8}\ \Omega$
(ii)[1.0]
The specific resistance of the combination of two cubes of length 50m in series will be:
  • (a)$10^{-6}\ \Omega\text{ m}$
  • (b)$2.5 \times 10^{-5}\ \Omega\text{ m}$
  • (c)$2 \times 10^{-6}\ \Omega\text{ m}$
  • (d)$50 \times 10^{-8}\ \Omega\text{ m}$

No answer yet.

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