Using properties of determinant, show that:
Using properties of determinant, show that:
$\begin{vmatrix} b - c & c - a & a - b \\ c - a & a - b & b - c \\ 2(a - b) & 2(b - c) & 2(c - a) \end{vmatrix} = 0$
Given: $\begin{vmatrix} b - c & c - a & a - b \\ c - a & a - b & b - c \\ 2(a - b) & 2(b - c) & 2(c - a) \end{vmatrix}$
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From ISC 2026 Mathematics Paper 1, question 2.