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Choose the correct option.
If A = [0 5 -y; -5 0 x; y -x 0], then the value of A⁻¹ · (adj A) A is:
If $A = \begin{bmatrix} 0 & 5 & -y \\ -5 & 0 & x \\ y & -x & 0 \end{bmatrix}$, then the value of $A^{-1} \cdot (\operatorname{adj} A) A$ is:
- (a)$A^2$
- (b)$I$
- (c)$0$
- (d)$A$
Answer
Answer
Official answer keyCorrect option: (c)
Answer: (c) $0$