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Choose the correct option.
Given two events A and B such that P(A/B) = 0.25 and P(A ∩ B) = 0· 12. The value P(A' ∩ B) is…
Given two events $A$ and $B$ such that $P(A/B) = 0.25$ and $P(A \cap B) = 0\cdot 12$.
The value $P(A' \cap B)$ is: (Understanding)
- (a)$0\cdot 36$
- (b)$0\cdot 48$
- (c)$0\cdot 88$
- (d)$0\cdot 036$
Answer
Answer
Official answer keyCorrect option: (a)
Answer: (a) $0\cdot 36$
$P(B) = \frac{P(A \cap B)}{P(A/B)} = \frac{0.12}{0.25} = 0.48$, so $P(A' \cap B) = P(B) - P(A \cap B) = 0.48 - 0.12 = 0.36$.