- (a)$-4$
- (b)$4$
- (c)$-16$
- (d)$16$
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All 134 questions of the ISC Mathematics 2025 Competency Focused Questions (CFQ), in printed order, in full. Tap "Show answer" under a question to see its answer.
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Assertion: The relation $f: \{m, n, p, q\} \to \{11, 12, 13, 14\}$ defined by $f = \{(m, 11), (n, 12), (p, 13)\}$ is a bijective function.
Reason: The function $f: \{m, n, p\} \to \{11, 12, 13, 14\}$ such that $f = \{(m, 11), (n, 12), (p, 13)\}$ is one-one.
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Assertion: Let $A = \begin{bmatrix} d_1 & 0 & 0 \\ 0 & d_2 & 0 \\ 0 & 0 & d_3 \end{bmatrix}$, then $A^{-1} = \begin{bmatrix} d_1^{-1} & 0 & 0 \\ 0 & d_2^{-1} & 0 \\ 0 & 0 & d_3^{-1} \end{bmatrix}$
Reason: If $A$ is a diagonal matrix, then $A^{-1}$ exists, it is also a diagonal matrix.
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Assertion: If $E_1$ and $E_2$ are two mutually exclusive events associated with a random experiment and $E$ is an event such that $P(E) \neq 0$, then $P\left(\frac{E_1 \cup E_2}{E}\right) = P\left(\frac{E_1}{E}\right) + P\left(\frac{E_2}{E}\right)$.
Reason: For two mutually exclusive events $E_1$ and $E_2$, $P(E_1 \cap E_2) = 0$.
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Assertion: $\vec{PQ} \times (\vec{RS} + \vec{ST}) \neq \vec{0}$.
Reason: $\vec{PQ} \times \vec{RS} = \vec{0}$ and $\vec{PQ} \times \vec{ST} \neq \vec{0}$.

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Assertion: A company uses a demand function $p = \frac{a}{x+b} - c$, where $a, b, c \in \mathbb{R}$ and $x = \text{number of units}$. The Marginal Revenue decreases with the increase of $x$.
Reason: $\frac{d}{dx}(MR) < 0$, where $0 < a < b$.
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Assertion: The curve in the graph below is not a one-one function:
Reason: If any straight line parallel to y-axis does not cut the curve at more than one point, then that curve represents a function.

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Assertion: Let $f(x)$ be a polynomial function of degree 7 such that $\frac{d}{dx}(f(x)) = (x-2)^3(x+1)^2(7x-2)$ has a local minimum at $x = -1$.
Reason: Let $f$ have first derivative at $c$ such that $f'(c) = 0$ and $f'(x) > 0, \forall x \in (c-\delta, c)$, $f'(x) < 0, \forall x \in (c, c+\delta)$, then $c$ is a point of local minimum.
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Assertion: If $y = \sin^{-1}(x\sqrt{x})$, then $\frac{dy}{dx} = \frac{3\sqrt{x}}{2\sqrt{1-x^3}}$.
Reason: $\frac{d}{dx}(\sin^{-1} x) = \frac{1}{\sqrt{1-x^2}}, |x| \le 1$.
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Assertion: Degree of the differential equation $a\left(\frac{dy}{dx}\right)^2 + b\frac{dy}{dx} = c$ cannot be determined.
Reason: If each term involving derivatives of a differential equation is a polynomial (or can be expressed as a polynomial) then the highest exponent of the highest order derivative is called the degree of the differential equation.
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Assertion: Maximum value of the function is 0.
Reason: Minimum value of the function approaches $\infty$.

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| Face | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| Probability | 0.10 | 0.24 | 0.19 | 0.18 | 0.15 | 0.14 |
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| Thickness $t$ (mm) | Length $l$ (cm) |
|---|---|
| 9 | 5.9 |
| 8 | 4.1 |
| 3 | 2.1 |
| 6 | 1.8 |
| 4 | 3.0 |
| 10 | 7.8 |
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| $x$ | -2 | 0 | 3 |
|---|---|---|---|
| $f(x)$ | -12 | -4 | 8 |
| $g(x)$ | 0 | -12 | 30 |
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| X | Y | |
|---|---|---|
| Mean | 15 | 75 |
| Standard Deviation (SD) | 4 | 10 |
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| Popcorn revenue (‘x’) | Drinks revenue (‘y’) |
|---|---|
| 14 | 22 |
| 12 | 23 |
| 12 | 17 |
| 14 | 24 |
| 16 | 18 |
| 10 | 25 |
| 13 | 23 |
| 12 | 24 |
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