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If , then the value of is:
If $A = \begin{bmatrix} 0 & 5 & -y \\ -5 & 0 & x \\ y & -x & 0 \end{bmatrix}$, then the value of $A^{-1} \cdot (\operatorname{adj} A) A$ is:
- (a)$A^2$
- (b)$I$
- (c)$0$
- (d)$A$
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From ISC 2025 Practice Mathematics, question 6.