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If and are two mutually exclusive events associated with a random experiment and is an event such…
Assertion: If $E_1$ and $E_2$ are two mutually exclusive events associated with a random experiment and $E$ is an event such that $P(E) \neq 0$, then $P\left(\frac{E_1 \cup E_2}{E}\right) = P\left(\frac{E_1}{E}\right) + P\left(\frac{E_2}{E}\right)$.
Reason: For two mutually exclusive events $E_1$ and $E_2$, $P(E_1 \cap E_2) = 0$.
If $E_1$ and $E_2$ are two mutually exclusive events associated with a random experiment and $E$ is an event such that: $P(E) \neq 0$.
Assertion (A): $P\left(\frac{E_1 \cup E_2}{E}\right) = P\left(\frac{E_1}{E}\right) + P\left(\frac{E_2}{E}\right)$.
Reason (R): For two mutually exclusive events $E_1$ and $E_2$, $P(E_1 \cap E_2) = 0$.
- (a)Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation for Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (A) is not the correct explanation for Assertion (A).
- (c)Assertion (A) is true, and Reason (R) is false.
- (d)Assertion (A) is false, and Reason (R) is true.
Answer
No answer yet.
From ISC 2025 Practice Mathematics, question 38.