If A=1 and B=0 then find the value of (A' + 1) · B

$(A'+1) \cdot B$ for $A=1, B=0$: $A'=0$, so $A'+1 = 0+1 = 1$ (Identity Law: anything OR 1 = 1). Then $1 \cdot B = 1 \cdot 0 = 0$.