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Answer the following.
The dual of (X' + 1) · (Y' + 0) = Y' is:
The dual of $(X' + 1) \cdot (Y' + 0) = Y'$ is:
- (a)$X \cdot 0 + Y \cdot 1 = Y$
- (b)$X' \cdot 1 + Y' \cdot 0 = Y'$
- (c)$X' \cdot 0 + Y' \cdot 1 = Y'$
- (d)$(X' + 0) + (Y' + 1) = Y'$
Answer
Answer
Correct option: (c)
Answer: (c) $X' \cdot 0 + Y' \cdot 1 = Y'$
For the dual, interchange $+$ and $\cdot$ and interchange 0 and 1, leaving the variables and their complements unchanged.