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The de Broglie wavelength of an electron in the first Bohr’s orbit of hydrogen atom is equal to:
- (a)diameter of the first orbit.
- (b)circumference of the first orbit.
- (c)radius of the second orbit.
- (d)$h/2\pi$.
Answer
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From ISC 2025 Specimen Physics Paper 1, question 1(A)(iv).