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Moving charges and magnetism - ISC Class 12 Physics Questions with Answers, Page 3

99 past-paper questions on Moving charges and magnetism from ISC Class 12 Physics papers (2027-2018), newest first, in full. Questions 41-60 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2025 · 1 mark · MCQOpen: An ideal Moving Coil Galvanometer (MCG) cannot be used as an ammeter to measure…

Choose the correct option.

An ideal Moving Coil Galvanometer (MCG) cannot be used as an ammeter to measure the value of current in a given circuit. The following reasons are: (i) it has a high current sensitivity value, (ii) for a minimal amount of current the galvanometer deflection will be maximum, (iii) it has a low least count.
  • (a)(i) and (ii)
  • (b)(i) and (iii)
  • (c)(ii) and (iii)
  • (d)(i), (ii), and (iii)

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2025 · 3 marks · Fill inOpen: A toroid is a hollow non-conducting circular ring, on which a large number of…

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A toroid is a hollow non-conducting circular ring, on which a large number of turns of a conducting wire are closely wound. If a solenoid is bent into a circular shape and the ends are joined, we get a toroid. Consider a toroid having centre O, number of turns N and each carrying a current I. By Ampere's law, in the case of a toroid: STEP 1: $\oint B \cdot dl = \mu_0\text{ (Total current)} = \mu_0$ ____ $I$ (Rewrite STEP 1 and fill in the blank with an appropriate substitution) STEP 2: $B$ ____ $= \mu_0 NI$ (Rewrite STEP 2 and fill in the blank with an appropriate substitution) $\therefore B = \frac{\mu_0 NI}{2\pi r} = \mu_0 I \left[\frac{N}{2\pi r}\right]$ If n is the number of turns per unit length, then $n = \frac{N}{2\pi r}$ STEP 3: $B = \mu_0$ ____ $I$ (Rewrite STEP 3 and fill in the blank with an appropriate substitution)

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2025 · 3 marks · DerivationOpen: Using Ampere's circuital law, obtain an expression for magnetic field 'B' at a…

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Using Ampere's circuital law, obtain an expression for magnetic field 'B' at a point 'P' which is at a perpendicular distance '$r$' from an infinitely long straight conductor, carrying a current '$I$'.

Given: Ampere's circuital law $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$

To show: Expression for magnetic field $B = \frac{\mu_0 I}{2\pi r}$

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2025 · 1 mark · MCQOpen: Lorenz's force is:

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Lorenz's force is:
  • (a)the vector sum of electrostatic and magnetic force acting on a moving charged particle.
  • (b)the sum of electrostatic and magnetic force acting on a moving charged particle.
  • (c)electrostatic force acting on a charged particle only.
  • (d)the magnetic force acting on a moving charged particle only.

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