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Solve the following.
Two moving coil galvanometers G₁ and G₂ are identical except that they have 50 turns and 20 turns…
Two moving coil galvanometers $G_1$ and $G_2$ are identical except that they have 50 turns and 20 turns and resistance of $10\,\Omega$ and $1\,\Omega$ respectively. Perform necessary calculations to check which one has greater voltage sensitivity.
Answer
Answer
Official answer keyVoltage sensitivity $\beta = \dfrac{BAN}{CR}$ ($C$ = torsion constant per unit twist, same for identical galvanometers).
$\beta(G_1) = \dfrac{BA\times 50}{C\times 10} = 5\dfrac{BA}{C}$
$\beta(G_2) = \dfrac{BA\times 20}{C\times 1} = 20\dfrac{BA}{C}$
Final answer: G2 (20BA/C against 5BA/C)