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Using Biot-Savart law, show that magnetic flux density ‘B’ at the centre of a current carrying…
Using Biot-Savart law, show that magnetic flux density ‘B’ at the centre of a current carrying circular coil of radius R is given by:
$B = \frac{\mu_0 I}{2R}$
where the terms have their usual meaning.
Given: A circular coil of radius R carrying current I, and Biot-Savart law $dB = \frac{\mu_0}{4\pi} \frac{I dl \sin\theta}{r^2}$
To show: $B = \frac{\mu_0 I}{2R}$
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From ISC 2024 Physics Paper 1, question 11.