Derive the following.
Show that intensity of electric field $E$ at a point in broadside on position is given by:
$E = \left(\frac{1}{4\pi\varepsilon_0}\right) \frac{p}{(r^2 + l^2)^{3/2}}$,
where the terms have their usual meaning.
Given: Electric dipole in broadside on position
To show: $E = \left(\frac{1}{4\pi\varepsilon_0}\right) \frac{p}{(r^2 + l^2)^{3/2}}$
No answer yet.