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Electric Charges and Fields - ISC Class 12 Physics Questions with Answers, Page 2

45 past-paper questions on Electric Charges and Fields from ISC Class 12 Physics papers (2027-2018), newest first, in full. Questions 21-40 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2025 · 1 mark · MCQOpen: A non-conducting sphere A, attached to an insulated handle is given a charge …

Choose the correct option.

A non-conducting sphere A, attached to an insulated handle is given a charge $+q$. It is brought near a non-conducting sphere B, having a charge $+Q$, placed on a platform attached to a spring and placed at a vertical distance R from sphere B. The spring compresses by a distance $d_1$. Now, if sphere B is replaced by a similar conducting sphere and sphere A is brought vertically at the same distance from B, without touching it, the spring compresses by a distance $d_2$. Choose the correct option based on the above situation and diagram:
  • (a)$d_2 > d_1$
  • (b)$d_2 < d_1$
  • (c)$d_2 = d_1$
  • (d)insufficient information to compare $d_2$ and $d_1$.

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2025 · 3 marks · DerivationOpen: Derive an expression for electric field intensity (E) at a point which lies on…

Derive the following.

Derive an expression for electric field intensity (E) at a point which lies on the axis of an electric dipole (having length $2l$ and dipole moment P) and which is at a distance '$r$' from its centre.

Given: An electric dipole of length $2l$ and dipole moment P

To show: Electric field intensity (E) at an axial point at a distance '$r$' from its centre

No answer yet.

2023 · 1 mark · MCQOpen: A hollow sphere of radius has a point charge at its centre. Electric flux…

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A hollow sphere of radius $R$ has a point charge $Q$ at its centre. Electric flux emanating from it is $\phi$. If both the charge and the radius of the sphere be doubled, electric flux emanating from the sphere will:
  • (a)remain the same.
  • (b)become $2\phi$
  • (c)become $4\phi$
  • (d)become $8\phi$

No answer yet.

2023 · 3 marks · DerivationOpen: Show that intensity of electric field at a point in broadside position of an…

Derive the following.

Show that intensity of electric field at a point in broadside position of an electric dipole is given by: $E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{p}{(r^2 + l^2)^{3/2}}$ where the terms have their usual meaning.

To show: $E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{p}{(r^2 + l^2)^{3/2}}$

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2022 · 1 mark · MCQOpen: In figure 3 given below, Electric field intensity ‘E’ at a point P, at a…

Choose the correct option.

In figure 3 given below, Electric field intensity ‘E’ at a point P, at a perpendicular distance ‘r’ from an infinitely long line charge X’X having linear charge density $\lambda$ is given by:
  • (a)$E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{2\lambda}{r^2}$
  • (b)$E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{2\lambda}{r}$
  • (c)$E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{\lambda}{r^2}$
  • (d)$E = \left(\frac{1}{4\pi\epsilon_0}\right) \frac{\lambda}{r}$
Figure for this question

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2022 · 1 mark · MCQOpen: The surface charge density of a conductor, in the absence of another conductor:

Choose the correct option.

The surface charge density of a conductor, in the absence of another conductor:
  • (a)Is proportional to the charge on the conductor and its surface area
  • (b)Inversely proportional to the charge and directly proportional to the surface area
  • (c)Directly proportional to the charge and inversely proportional to the surface area
  • (d)Inversely proportional to the charge and the surface area

No answer yet.

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