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Choose the correct option.
The value of |1 log_a b; log_b a 1| is:
The value of $\begin{vmatrix} 1 & \log_a b \\ \log_b a & 1 \end{vmatrix}$ is:
- (a)$1 - \log_a b$
- (b)$1 - \frac{\log b}{\log a}$
- (c)0
- (d)$\log_a b - 1$
Answer
Answer
Correct option: (c)
Answer: (c) 0
The determinant is $1\cdot 1-\log_a b\cdot\log_b a$.
Since $\log_b a=\frac{1}{\log_a b}$, the product is 1. Hence the value is $1-1=0$.