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Choose the correct option.
The value of tan⁻¹ √3 - sec⁻¹(-2) is equal to
The value of $\tan^{-1} \sqrt{3} - \sec^{-1}(-2)$ is equal to
- (a)$\frac{\pi}{3}$
- (b)$\frac{2\pi}{3}$
- (c)$-\frac{\pi}{3}$
- (d)$\frac{\pi}{4}$
Answer
Answer
Correct option: (c)
Answer: (c) $-\frac{\pi}{3}$
$\tan^{-1}\sqrt{3} = \frac{\pi}{3}$ and $\sec^{-1}(-2) = \pi - \frac{\pi}{3} = \frac{2\pi}{3}$.
Hence $\frac{\pi}{3} - \frac{2\pi}{3} = -\frac{\pi}{3}$.