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Mathematics20204 marksNumericalInverse Trigonometric Functions

Answer the following.

Evaluate: cos(2cos⁻¹ x + sin⁻¹ x) at x = 1/5.

Evaluate: $\cos\left(2\cos^{-1} x + \sin^{-1} x\right)$ at $x = \frac{1}{5}$.

Answer

Answer

Using $\sin^{-1}x = \frac{\pi}{2} - \cos^{-1}x$: $2\cos^{-1}x + \sin^{-1}x = \cos^{-1}x + \frac{\pi}{2}$ $\cos\left(\cos^{-1}x + \frac{\pi}{2}\right) = -\sin(\cos^{-1}x) = -\sqrt{1 - x^2}$ At $x = \frac{1}{5}$: $-\sqrt{1 - \frac{1}{25}} = -\frac{\sqrt{24}}{5}$

Final answer: $-\frac{2\sqrt{6}}{5}$