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Solve the following.
The angle between the line (x+1)/1 = (y-1)/2 = (z-2)/2 and the plane 2x - y + √kz + 4 = 0 is α…
The angle between the line $\frac{x+1}{1} = \frac{y-1}{2} = \frac{z-2}{2}$ and the plane $2x - y + \sqrt{k}z + 4 = 0$ is $\alpha$. Given $\sin\alpha = \frac{1}{3}$, what will be the value of $k$?
Answer
Answer
Official answer key$\frac{5}{3}$
Final answer: $\frac{5}{3}$