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Since $A + A' = 1$, $(A + A')' = 1' = 0$ for every value of A. The output is always 0, so it is a Contradiction.
Answer the following.
Verify if (A + A')' is a Tautology, Contradiction, or a Contingency.
Verify if $(A + A')'$ is a Tautology, Contradiction, or a Contingency.
Answer
Answer
| A | A' | A + A' | (A + A')' |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 1 | 0 |