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Solve the following.

Calculate the E°_(cell) of the following if the cell potential (E_(cell)) is 0·59 V. (Given: Ni /…

Calculate the $E^\circ_{\text{cell}}$ of the following if the cell potential ($E_{\text{cell}}$) is $0\cdot59\text{ V}$. (Given: $\text{Ni} / \text{Ni}^{2+}(0\cdot1\text{M}) \parallel \text{Cu}^{2+}(0\cdot01\text{M}) / \text{Cu}$)

Answer

Answer

Cell reaction: $\mathrm{Ni+Cu^{2+}\rightarrow Ni^{2+}+Cu}$, $n=2$, $Q=\frac{[\mathrm{Ni^{2+}}]}{[\mathrm{Cu^{2+}}]}=\frac{0.1}{0.01}=10$. $E=E^\circ-\frac{0.059}{2}\log Q$, so $0.59=E^\circ-0.0295\times1$, $E^\circ=0.6195\approx0.62\text{ V}$

Final answer: 0.62 V