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Arrange the following in the order asked.
The standard reduction electrode potential (E°) of some metals is given below: Metal E° Ag⁺/Ag…
The standard reduction electrode potential ($E^\circ$) of some metals is given below:
Arrange these metals in the increasing order of their reducing power. Justify the order.
| Metal | $E^\circ$ |
|---|---|
| $\text{Ag}^+/\text{Ag}$ | $+0\cdot80\text{V}$ |
| $\text{Mg}^{2+}/\text{Mg}$ | $-2\cdot37\text{V}$ |
| $\text{Li}^+/\text{Li}$ | $-3\cdot05\text{V}$ |
| $\text{Cu}^{2+}/\text{Cu}$ | $+0\cdot34\text{V}$ |
| $\text{Fe}^{2+}/\text{Fe}$ | $-0\cdot44\text{V}$ |
Answer
Answer
Official answer keyOrder, first to last: Ag, Cu, Fe, Mg, Li
Increasing order of reducing power: Ag < Cu < Fe < Mg < Li. Reducing power is inversely related to the reduction potential: the lower (more negative) the standard reduction potential, the greater the tendency of the metal to lose electrons, so the greater its reducing power.