Prashnikaप्रश्निका
‹ Back to the paper

Solve the following.

The resistance of a conductivity cell with solution is . When the same cell is filled with…

Chemistry20235 marksNumerical
(a)[2.5]
The resistance of a conductivity cell with $0\cdot1\text{ M}$ $\text{KCl}$ solution is $200\text{ ohm}$. When the same cell is filled with $0\cdot02\text{ M}$ $\text{NaCl}$ solution, the resistance is $1100\text{ ohm}$. If the conductivity of $0\cdot1\text{ M}$ $\text{KCl}$ solution is $0\cdot0129\text{ ohm}^{-1}\text{ cm}^{-1}$, calculate the cell constant and molar conductivity of $0\cdot02\text{ M}$ $\text{NaCl}$ solution.
(b)[2.5]
The emf ($E^\circ_{\text{cell}}$) of the following reaction is $0\cdot89\text{ V}$: $3\text{Sn}^{4+} + 2\text{Cr} \rightarrow 3\text{Sn}^{2+} + 2\text{Cr}^{3+}$ Calculate the value of $\Delta G^\circ$ for the reaction. Predict whether the above reaction will be spontaneous or not.

Answer

No answer yet.

Electrochemistry

From ISC 2023 Chemistry Paper 1, question 21(ii).

Check your working with the Chemistry numericals calculator: solutions, electrochemistry and kinetics formulas: fill in what you know and get the rest.