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Solve the following.
If 200 cm³ of an aqueous solution of a protein contains 1·26 g of protein, the osmotic pressure of…
If $200\text{ cm}^3$ of an aqueous solution of a protein contains $1\cdot26\text{ g}$ of protein, the osmotic pressure of the solution at $300\text{ K}$ is found to be $2\cdot57 \times 10^{-3}\text{ atm}$.
Calculate the molar mass of protein.
($R = 0\cdot0821\text{ L atm K}^{-1}\text{ mol}^{-1}$)
Answer
Answer
$\pi V = \dfrac{w}{M}RT$, so $M = \dfrac{wRT}{\pi V}$
$M = \dfrac{1.26\ \mathrm{g} \times 0.0821\ \mathrm{L\,atm\,K^{-1}mol^{-1}} \times 300\ \mathrm{K}}{2.57\times10^{-3}\ \mathrm{atm} \times 0.2\ \mathrm{L}} = 60377\ \mathrm{g\,mol^{-1}}$
Final answer: 60377 g mol^-1