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Answer the following.
K₂Cr₂O₇ + H₂SO₄ + Na₂SO₃ longrightarrow
$\text{K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 + \text{Na}_2\text{SO}_3 \longrightarrow$
Answer
Answer
Equation: $\mathrm{K_{2}Cr_{2}O_{7}} + 4\mathrm{H_{2}SO_{4}} + 3\mathrm{Na_{2}SO_{3}} \longrightarrow \mathrm{K_{2}SO_{4}} + \mathrm{Cr_{2}(SO_{4})_{3}} + 3\mathrm{Na_{2}SO_{4}} + 4\mathrm{H_{2}O}$
Sodium sulphite is oxidised to sulphate and the orange dichromate is reduced to green $\mathrm{Cr^{3+}}$.