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Write the chemical equation for the following.
CH₃CH₂Br + AgCN (alc.) →
$\text{CH}_3\text{CH}_2\text{Br} + \text{AgCN (alc.)} \rightarrow $
Answer
Answer
Equation: $\mathrm{CH_{3}CH_{2}Br} + \mathrm{AgCN} \xrightarrow{\text{alc.}} \mathrm{CH_{3}CH_{2}NC} + \mathrm{AgBr}$
Product: ethyl isocyanide
Ethyl bromide with alcoholic AgCN (largely covalent) gives ethyl isocyanide as the main product.