Rohan, a patient of thyroid disorder, was given certain amount of radioactive Iodine-131 as a part…
Rohan, a patient of thyroid disorder, was given certain amount of radioactive Iodine-131 as a part of his treatment. The half-life of Iodine-131 is 8 days. If the radioactive decay follows first order kinetics, how long will it take for the radioactivity to fall to $25\%$ of its initial value?
Answer
Answer
AIWritten by AI (gemini) - it can contain mistakes.
Given: $t_{1/2} = 8\text{ days}$, remaining amount $A = 25\% = \frac{A_0}{4} = A_0 \left(\frac{1}{2}\right)^2$.
Number of half-lives $n = 2$.
Total time $t = n \times t_{1/2} = 2 \times 8 = 16\text{ days}$.
Final answer: 16 days
Final answer: 16 days
From ISC 2027 Specimen Chemistry Paper 1, question 5.