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de Broglie wavelength of a moving particle is . Its momentum is given by:
de Broglie wavelength of a moving particle is $\lambda$. Its momentum is given by:
- (a)$h\lambda$
- (b)$\frac{h}{\lambda}$
- (c)$\frac{\lambda}{h}$
- (d)Zero
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From ISC 2018 Specimen Physics Paper 1, question 1(A)(iv).