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The order and the degree of differential equation are:
The order and the degree of differential equation $\left[1 + \left(\frac{dy}{dx}\right)^2\right]^{\frac{1}{3}} = \frac{d^2y}{dx^2}$ are:
- (a)$2$ and $\frac{3}{2}$
- (b)$2$ and $3$
- (c)$3$ and $4$
- (d)$2$ and $1$
Answer
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From ISC 2024 Mathematics Paper 1, question 1(ii).