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Choose the correct option.
If events A and B are mutually exclusive, such that P(A) = 1/5 and P(B) = 2/3, then the value of…
If events $A$ and $B$ are mutually exclusive, such that $P(A) = \frac{1}{5}$ and $P(B) = \frac{2}{3}$, then the value of $P(A \cup B)$ is:
- a$\frac{11}{15}$
- b$\frac{3}{15}$
- c$\frac{14}{15}$
- d$\frac{13}{15}$
Answer
Answer
Correct option: d
Answer: (d) $\frac{13}{15}$
For mutually exclusive events $A$ and $B$, $P(A \cap B) = 0$. Therefore, $P(A \cup B) = P(A) + P(B) = \frac{1}{5} + \frac{2}{3} = \frac{13}{15}$.