If the demand function is given by , where the price is ₹ per unit and the manufacturer produces…

If the demand function is given by $x = \frac{600-p}{8}$, where the price is ₹ $p$ per unit and the manufacturer produces $x$ units per week at the total cost of ₹ $(x^2 + 78x + 2500)$, find the value of $x$ for which the profit is maximum.