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Choose the correct option.
The value of ∫₀¹ |x + 1| dx is:
The value of $\int_{0}^{1} |x + 1| \, dx$ is:
- a$0$
- b$\frac{3}{2}$
- c$\frac{1}{2}$
- d$\frac{-3}{2}$
Answer
Answer
Correct option: b
Answer: (b) $\frac{3}{2}$
On $[0, 1]$, $x + 1 > 0$, so $\int_0^1 (x + 1)\,dx = \left[\frac{x^2}{2} + x\right]_0^1 = \frac{3}{2}$.