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Solve the following.
Evaluate: ∫ (2x³ - 1)/(x⁴ + x) dx
Evaluate: $\int \frac{2x^3 - 1}{x^4 + x} \, dx$
Answer
Answer
Official answer key$\int \frac{2x^3 - 1}{x^4 + x}\,dx$
Dividing both numerator and denominator by $x$ we get
$= \int \frac{2x - \frac{1}{x^2}}{x^2 + \frac{1}{x}}\,dx$. Let $x^2 + \frac{1}{x} = t \Rightarrow \left(2x - \frac{1}{x^2}\right)dx = dt$
$= \int \frac{dt}{t}$
$= \log_e|t| + c$
$= \log_e\left|x^2 + \frac{1}{x}\right| + c$
Final answer: $\log_e\left|x^2 + \frac{1}{x}\right| + c$