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If and , show that the function is one – one onto. Hence, find .
If $f : A \to A$ and $A = \mathbb{R} - \left\\{\frac{8}{5}\right\\}$, show that the function $f(x) = \frac{8x + 3}{5x - 8}$ is one – one onto. Hence, find $f^{-1}$.
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From ISC 2019 Mathematics Paper 1, question 2.