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Solve for :
Solve for $x$:
$\tan^{-1}\left(\frac{x - 1}{x - 2}\right) + \tan^{-1}\left(\frac{x + 1}{x + 2}\right) = \frac{\pi}{4}$
Answer
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From ISC 2019 Mathematics Paper 1, question 3(a).
No answer yet.
From ISC 2019 Mathematics Paper 1, question 3(a).