There are two curves given in the first quadrant as: . What are the points of intersection of both…

In the first quadrant the circle $x^2 + y^2 = \pi^2$ and the curve $y = \sin x$ meet where $\sin^2 x = \pi^2 - x^2$. For $0 \le x < \pi$ the circle is higher than the sine curve (e.g. at $x = 0$, $\pi$ against $0$), and they meet only at $x = \pi$, where $y = \sin\pi = 0$ and $\pi^2 + 0 = \pi^2$. So the only point of intersection in the first quadrant is $(\pi, 0)$. (The printed key lists $(0,0)$ and $(0,\pi)$, but neither lies on both curves.)