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The equation of the line passing (1, -1, 0) and parallel to the line is:

Mathematics20222 marksMCQ
The equation of the line passing (1, -1, 0) and parallel to the line $\frac{x-1}{1} = \frac{y+2}{-2} = \frac{z+1}{-1}$ is:
  • (a)$\frac{x-1}{1} = \frac{y+1}{-2} = \frac{z}{-1}$
  • (b)$\frac{x-1}{2} = \frac{y+2}{-1} = \frac{z+1}{-3}$
  • (c)$\frac{x-6}{1} = \frac{y-2}{-2} = \frac{z+1}{3}$
  • (d)$\frac{x-2}{-2} = \frac{y+2}{-2} = \frac{z+3}{-1}$

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Three-dimensional Geometry

From ISC 2022 Specimen Mathematics Paper 1, question 27.