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Solve the following.
Find the derivative of y = log x + 1/x with respect to x.
Find the derivative of $y = \log x + \frac{1}{x}$ with respect to $x$.
Answer
Answer
Differentiating: log(x) + 1/x
$y = \log x + \frac{1}{x}$
$\frac{dy}{dx} = \frac{1}{x} - \frac{1}{x^2}$
Final answer: $\frac{1}{x} - \frac{1}{x^2}$