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Relations and Functions - ISC Class 12 Mathematics Questions with Answers, Page 2

58 past-paper questions on Relations and Functions from ISC Class 12 Mathematics papers (2027-2017), newest first, in full. Questions 21-40 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.

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2025 · 1 mark · MCQOpen: Consider the following graph of , : Statement 1: The function is one-one…
Consider the following graph of $f(x)$, $f: \mathbb{R} \to \mathbb{R}$: Statement 1: The function is one-one function. Statement 2: The function is onto function.
  • (a)Statement 1 is true and Statement 2 is false.
  • (b)Statement 2 is true and Statement 1 is false.
  • (c)Both the statements are true.
  • (d)Both the statements are false.
Figure for this question

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2025 · 1 mark · Assertion-reasonOpen: If Set has elements, Set has elements and , then the number of one-one…

Assertion: If Set $A$ has $m$ elements, Set $B$ has $n$ elements and $n < m$, then the number of one-one function(s) from $A \to B$ is zero.

Reason: A function $f: A \to B$ is defined only if all elements in Set $A$ have an image in Set $B$.

  • (a)Both Assertion and Reason are true and Reason is the correct explanation for Assertion.
  • (b)Both Assertion and Reason are true but Reason is not the correct explanation for Assertion.
  • (c)Assertion is true and Reason is false.
  • (d)Assertion is false and Reason is true.

No answer yet.

2025 · 4 marks · Long answerOpen: A part of the graph of the function is shown below: Answer the following…
A part of the graph of the function $f(x) = 2x^3 - 3x^2 - 12x + 8, x \in \mathbb{R}$ is shown below: Answer the following questions.
Figure for this question
(a)
Explain why ‘f’ does not have an inverse.
(b)
The domain of ‘f’ is now restricted to $a \le x \le b$ where $a < 0$ and $b > 0$. $a$ and $b$ are chosen so that f has an inverse and the interval $[a, b]$ is as large as possible. Find the domain and range of $f^{-1}$.

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2025 · 1 mark · MCQOpen: Statement I: given by , is neither injective nor surjective. Statement II…
Statement I: $f: \mathbb{R} \to \mathbb{R}$ given by $f(x) = \frac{1}{x} - 2$, is neither injective nor surjective. Statement II: $f: \mathbb{Z} \to \mathbb{Z}$ given by $f(x) = \sqrt[3]{x^9}$, is neither injective nor surjective.
  • (a)Both the statements are true.
  • (b)Both the statements are false.
  • (c)Statement I is true, and Statement II is false.
  • (d)Statement I is false, and Statement II is true.

No answer yet.

2025 · 1 mark · Assertion-reasonOpen: The relation defined by is a bijective function. Assertion (A): The relation…

Assertion: The relation $f: \{m, n, p, q\} \to \{11, 12, 13, 14\}$ defined by $f = \{(m, 11), (n, 12), (p, 13)\}$ is a bijective function.

Reason: The function $f: \{m, n, p\} \to \{11, 12, 13, 14\}$ such that $f = \{(m, 11), (n, 12), (p, 13)\}$ is one-one.

Assertion (A): The relation $f: \{m, n, p, q\} \to \{11, 12, 13, 14\}$ defined by $f = \{(m, 11), (n, 12), (p, 13)\}$ is a bijective function. Reason (R): The function $f: \{m, n, p\} \to \{11, 12, 13, 14\}$ such that $f = \{(m, 11), (n, 12), (p, 13)\}$ is one-one.
  • (a)Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
  • (b)Both Assertion (A) and Reason (R) are true, and Reason (R) is not the correct explanation of Assertion (A).
  • (c)Assertion (A) is true; Reason (R) is false.
  • (d)Assertion (A) is false; Reason (R) is true.

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2024 · 2 marks · Short answerOpen: Let be defined as is invertible. Find .
Let $f: \mathbb{R} - \left\{-\frac{1}{3}\right\} \to \mathbb{R} - \{0\}$ be defined as $f(x) = \frac{5}{3x + 1}$ is invertible. Find $f^{-1}(x)$.

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2024 · 1 mark · MCQOpen: Let be a non-empty set. Statement 1: Identity relation on is Reflexive…
Let $A$ be a non-empty set. Statement 1: Identity relation on $A$ is Reflexive. Statement 2: Every Reflexive relation on $A$ is an Identity relation.
  • (a)Both the statements are true.
  • (b)Both the statements are false.
  • (c)Statement 1 is true and Statement 2 is false.
  • (d)Statement 1 is false and Statement 2 is true.

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2023 · 1 mark · MCQOpen: A relation on is given by . Then the relation is:
A relation $R$ on $\{1, 2, 3\}$ is given by $R = \{(1, 1), (2, 2), (1, 2), (3, 3), (2, 3)\}$. Then the relation $R$ is:
  • (a)Reflexive.
  • (b)Symmetric.
  • (c)Transitive.
  • (d)Symmetric and Transitive.

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2023 · 2 marks · DerivationOpen: Let and . If is a function defined by then show that is a one-one and an onto…
Let $A = \mathbb{R} - \{2\}$ and $B = \mathbb{R} - \{1\}$. If $f : A \to B$ is a function defined by $f(x) = \frac{x - 1}{x - 2}$ then show that $f$ is a one-one and an onto function.

Given: $f : A \to B \text{ defined by } f(x) = \frac{x - 1}{x - 2}$

To show: $f \text{ is a one-one and an onto function}$

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