Using integration, find the area of the region bounded between the line $x = 4$ and the parabola $y^2 = 16x$.
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Application of Integrals - ISC Class 12 Mathematics Questions with Answers, Page 2
28 past-paper questions on Application of Integrals from ISC Class 12 Mathematics papers (2027-2017), newest first, in full. Questions 21-28 are on this page, 20 to a page. Tap "Show answer" under a question to see its answer.
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Sketch the graph of $y = |x + 4|$. Using integration, find the area of the region bounded by the curve $y = |x + 4|$ and $x = -6$ and $x = 0$.
Draw: Graph of $y = |x + 4|$ and the region bounded by $x = -6$ and $x = 0$
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Draw a rough sketch of the curves $y^2 = x$ and $y^2 = 4 - 3x$ and find the area enclosed between them.
Draw: Rough sketch of the curves $y^2 = x$ and $y^2 = 4 - 3x$
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Draw a rough sketch and find the area bounded by the curve $x^2 = y$ and $x + y = 2$.
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Using integration, find the area of the following region:
$\{(x, y) : \frac{x^2}{9} + \frac{y^2}{4} \leq 1 \leq \frac{x}{3} + \frac{y}{2}\}$
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Sketch the graph of $y = |x + 4|$. Using integration, find the area of the region bounded by the curve $y = |x + 4|$ and $x = -6$ and $x = 0$.
Draw: Graph of $y = |x + 4|$ between $x = -6$ and $x = 0$
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Draw a rough sketch of the curve and find the area of the region bounded by curve $y^2 = 8x$ and the line $x = 2$.
Draw: Rough sketch of the curve $y^2 = 8x$ and the line $x = 2$
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Draw a rough sketch of the curve $y^2 = 4x$ and find the area of the region enclosed by the curve and the line $y = x$.
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