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A matrix N[11][8] is stored in the memory with each element requiring 2 bytes of storage. If the…
A matrix N[11][8] is stored in the memory with each element requiring 2 bytes of storage. If the base address at N[2][3] is 2140, find the address of N[7][5] when the matrix is stored in Row Major Wise.
Answer
Answer
AIRow Major formula relative to a known base address:
$Address(N[i][j]) = Base(N[2][3]) + W \times [(i-2)\times C + (j-3)]$, where $C$ = number of columns = 8, $W$ = 2 bytes
For $N[7][5]$:
$= 2140 + 2 \times [(7-2)\times 8 + (5-3)]$
$= 2140 + 2 \times [40+2]$
$= 2140 + 84$
Final answer: 2224
Final answer: 2224 bytes (address)
From ISC 2023 Specimen Computer Science Paper 1, question 2(ii).