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Following code gives a StackOverException. public class StackOverflow { public static void main() {…

Computer Science20252 marksShort answer
Following code gives a StackOverException.
public class StackOverflow
{
    public static void main()
    {
        callMe();
    }
    public static void callMe()
    {
        callMe();
    }
}
Stack is a data structure whereas recursion is related to a method. Why does the above code give an exception with stack overflow?

Answer

Answer

AI
Each call to callMe() creates a new activation record (return address, parameters, local variables) that is pushed onto the call stack, and since callMe() calls itself with no base/terminating condition, calls keep being pushed and none are ever popped. The stack has a fixed maximum size, and once that limit is exceeded by the endless pushes, the JVM throws a StackOverflowError (reported as a stack overflow exception).
Recursion

From ISC Computer Science - Competency Focused Practice Questions (CISCE, August 2024), question 58.

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