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How will you bring about the following conversion?
m-chlorotoluene from benzaldehyde.
Answer
Answer
Official answer keyEquations: $\mathrm{C_{6}H_{5}CHO} + \mathrm{Cl_{2}} \xrightarrow{\mathrm{FeCl_{3}}} \mathrm{m-ClC_{6}H_{4}CHO} + \mathrm{HCl}$ $\mathrm{m-ClC_{6}H_{4}CHO} \xrightarrow{\text{Zn-Hg}\text{/}\text{conc.}\text{ }\text{HCl}\text{,}\text{ }4\mathrm{[H]}} \mathrm{m-ClC_{6}H_{4}CH_{3}}$
Benzaldehyde $\xrightarrow{\mathrm{Cl_2/FeCl_3}}$ m-chlorobenzaldehyde $\xrightarrow{\mathrm{Zn\text{-}Hg/conc.\ HCl},\ 4[H]}$ m-chlorotoluene
From ISC 2025 Practice Chemistry, question 53(b).