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Identify the compounds in the following.
C₆H₅NH₂ + HNO₂ + HCl xrightarrow0--5°C [A] xrightarrowCu₂Cl₂/HCl [B]
$\text{C}_6\text{H}_5\text{NH}_2 + \text{HNO}_2 + \text{HCl} \xrightarrow{0\text{--}5^\circ\text{C}} [\text{A}] \xrightarrow{\text{Cu}_2\text{Cl}_2/\text{HCl}} [\text{B}]$
Answer
Answer
Equations: $\mathrm{C_{6}H_{5}NH_{2}} + \mathrm{HNO_{2}} + \mathrm{HCl} \xrightarrow{\text{0-5}\text{ }\text{C}} \mathrm{C_{6}H_{5}N_{2}Cl} + 2\mathrm{H_{2}O}$ $\mathrm{C_{6}H_{5}N_{2}Cl} \xrightarrow{\mathrm{Cu_{2}Cl_{2}}\text{/}\text{HCl}\text{,}\text{ }\text{Sandmeyer}\text{ }\text{reaction}} \mathrm{C_{6}H_{5}Cl} + \mathrm{N_{2}}$
A - benzenediazonium chloride: C6H5N2Cl
B - chlorobenzene: C6H5Cl
A = benzenediazonium chloride ($\mathrm{C_6H_5N_2Cl}$); B = chlorobenzene ($\mathrm{C_6H_5Cl}$)