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How will you bring about the following conversion?
Propan-1-ol to propyl cyanide
Answer
Answer
AIEquations: $\mathrm{CH_{3}CH_{2}CH_{2}OH} + \mathrm{SOCl_{2}} \longrightarrow \mathrm{CH_{3}CH_{2}CH_{2}Cl} + \mathrm{SO_{2}} + \mathrm{HCl}$ $\mathrm{CH_{3}CH_{2}CH_{2}Cl} + \mathrm{KCN} \xrightarrow{\text{alc.}} \mathrm{CH_{3}CH_{2}CH_{2}CN} + \mathrm{KCl}$
Propan-1-ol to propyl cyanide: chlorination with thionyl chloride, then nucleophilic substitution with KCN.
From ISC 2026 Improvement Chemistry Paper 1, question 15(i).