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Answer the following.
In the reaction 2NO + O₂ → 2NO₂, the rate law is rate = k[NO][O₂]². Write the order of reaction if…
In the reaction $2\text{NO} + \text{O}_2 \rightarrow 2\text{NO}_2$, the rate law is rate $= k[\text{NO}][\text{O}_2]^2$.
Write the order of reaction if $[\text{NO}]$ concentration is in large excess.
Answer
Answer
Order $= 2$.
If $[\text{NO}]$ is in large excess its concentration stays practically constant, so rate $= k'[\text{O}_2]^2$ with $k' = k[\text{NO}]$ (a pseudo second order reaction).