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Answer the following.
A solution of an organic compound was prepared by dissolving in of water. Calculate the osmotic…
A solution of an organic compound was prepared by dissolving $6\cdot8\text{ g}$ in $0\cdot1\text{ litre}$ of water. Calculate the osmotic pressure of this solution at $25^\circ\text{C}$.
(Molecular mass of organic compound $= 321\cdot45\text{ g mol}^{-1}$)
Answer
Answer
AIFormula:
$\Pi = \frac{w \times R \times T}{M \times V}$
Substitution:
$w = 6\cdot8\text{ g}$
$V = 0\cdot1\text{ L}$
$T = 25 + 273 = 298\text{ K}$
$M = 321\cdot45\text{ g mol}^{-1}$
$R = 0\cdot0821\text{ L atm K}^{-1}\text{mol}^{-1}$
$\Pi = \frac{6\cdot8\text{ g} \times 0\cdot0821\text{ L atm K}^{-1}\text{mol}^{-1} \times 298\text{ K}}{321\cdot45\text{ g mol}^{-1} \times 0\cdot1\text{ L}}$
$= \frac{166\cdot37}{32\cdot145} = 5\cdot18\text{ atm}$
Final answer: 5.18 atm
From ISC 2026 Chemistry Paper 1, question 19(ii).
Check your working with the Molar mass calculator: molar mass of any formula, hydrates too, with the working and percentage composition.
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